"This is slightly confusing,..."


by Eric Rogstad Jun 7 2016

In fact, I can also tell you that $~$\\log\_{10}(\\text{2,310,426})$~$ is between 6\.30 and 6\.48, because the last digit is worth more than a 2\-digit and less than a 3\-digit \(and I looked up the natural exchange rates for 2\-digits and 3\-digits in terms of 10\-digits\)\.

This is slightly confusing, because it's the first digit that's a 2.