Note also that a cycle's inverse is extremely easy to find: the inverse of $~$(a\_1 a\_2 \\dots a\_k)$~$ is $~$(a\_k a\_{k-1} \\dots a\_1)$~$\.

I'm curious if the inverse has any particular use in this field.

by Alexei Andreev Jun 14 2016

Note also that a cycle's inverse is extremely easy to find: the inverse of $~$(a\_1 a\_2 \\dots a\_k)$~$ is $~$(a\_k a\_{k-1} \\dots a\_1)$~$\.

I'm curious if the inverse has any particular use in this field.

## Comments

Patrick Stevens

None that I'm aware of, but I've found it convenient to know when I was doing exercises in a first course in group theory.