"Underline."

The other thing that this interpretation tells us is that the digit worth exactly half an $n$\-digit is the $\\sqrt{n}$\-digit, both because \(1\) if you want to use an $n$\-digit to store two $x$\-messages for some $x$, you need $x \\cdot x$ to be at most $n$; and \(2\) if you have a 50% chance of getting to use an $n$\-digit and a 50% chance of nothing, then that's equivalent on average to a certainty of a $\\sqrt{n}$\-digit\.

Underline.