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  text: 'The arithmetical hierarchy is a way of stratifying statements by how many "for every number" and "there exists a number" clauses they contain.\n\nSuppose we say "2 + 1 = 1 + 2".  Since this is only a statement about three specific numbers, this statement would occupy the lowest level of the arithmetical hierarchy, which we can equivalently call $\\Delta_0,$ $\\Pi_0,$ or $\\Sigma_0$ (the reason for using all three terms will soon become clear).\n\nNext, suppose we say, "For all numbers x: (1 + x) = (x + 1)."  This generalizes over *all* numbers - a universal quantifier - and then makes a statement about each particular number x, that (1 + x) = (x + 1), that involves no further quantifiers and can be verified immediately.  This statement is said to be in $\\Pi_1.$\n\nSuppose we say, "There exists a y such that $y^9 = 9^y.$"  This is a single existential quantifier.  To verify it by sheer brute force, we'd need to start from 0 and then consider successive integers y, checking for each particular y whether it was true that $y^9 = 9^y.$  Since the statement has a single existential quantifier over y, surrounding a statement that for any particular y is in $\\Delta_0,$ it is said to be in $\\Sigma_1.$\n\nSuppose we say, "For every number x, there exists a prime number y that is greater than x."  For any particular $c$ the statement "There is a prime number x that is greater than $c$" lies in $\\Sigma_1.$  Universally quantifying over all $c,$ outside of the $\\Sigma_1$ statement about any particular $c,$ creates a statement in $\\Pi_2.$\n\nSimilarly, the statement "There exists a number x such that, for every number y, $(x + y) > 10^9$ would be in $\\Sigma_2,$ since it adjoins a "there exists a number x..." to a statement that lies in $\\Pi_1$ for any particular $x.$\n\nGeneralizing, putting a "There exists an x..." quantifier outside a $\\Pi_n$ statement creates a $\\Sigma_{n+1}$ statement, and putting a "For all y" quantifier outside a $\\Sigma_n$ statement about y creates a $\\Pi_{n+1}$ statement.\n\nIf there are equivalent ways of formulating a sentence such that it can be seen to occupy both $\\Sigma_n$ and $\\Pi_n$, we say that it belongs to $\\Delta_n.$  \n\n# Consequences for epistemic reasoning\n\nStatements in $\\Sigma_1$ are *verifiable*.  Taking "There exists $y$ such that $y^9 = 9^y$" as the example, soon as we find any one particular $y$ such that $y^9 = 9^y,$ we can verify the central formula $y^9 = 9^y$ for that particular $y$ immediately, and then we're done.\n\nStatements in $\\Pi_1$ are *falsifiable*.  We can decisively demonstrate them to be wrong by finding a particular example where the core statement is false. \n\nSentences in $\\Delta_1$ are those which are both falsifiable and verifiable in finite time.\n\n$\\Pi_2$ and $\\Sigma_2$ statements are not definitely verifiable or falsifiable by brute force.  E.g. for a $\\Pi_2$ statement, "For every x there is a y", even after we've found a y for many particular x, we haven't tested all the x; and even if we've searched some particular x and not yet found any y, we haven't yet searched all possible y.  But statements in this class can still be probabilistically supported or countersupported by examples; each time we find an example of a y for another x, we might become a little more confident, and if for some x we fail to find a y after a long time searching, we might become a little less confident.\n\n# Subtleties\n\n## Bounded quantifiers don't count\n\nThe statement, "For every number $x,$ there exists a prime number $y$ smaller than $x^x$" is said to lie in $\\Pi_1$, not $\\Pi_2$.  Since the existence statement is bounded by $x^x$, a function which can itself be computed in bounded time, in principle we could just search through every possible $y$ that is less than $x^x$ and test it in bounded time.  For any particular $x,$ such as $x = 2,$ we could indeed replace the statement "There exists a prime number $y$ less than $2^2$" with the statement "Either 0 is a prime number, or 1 is a prime number, or 2 is a prime number, or 3 is a prime number" which contains no quantifiers at all.  Thus, in general within the arithmetical hierarchy, bounded quantifiers don't count.\n\nWe similarly observe that the statement  "For every number $x,$ there exists a prime number $y$ smaller than $x^x$" is *falsifiable* - we could falsify it by exhibiting some particular constant $c,$ testing all the numbers smaller than $c^c,$ and failing to find any primes.  (As would in fact be the case if we tested $c=1.$)\n\n## Similar adjacent quantifiers can be collapsed into a single quantifier\n\nSince bounded quantifiers don't count, it follows more subtly that we can combine adjacent quantifiers of the same type, since there are bounded ways to *encode* multiple numbers in a single number.  For example, the numbers x and y can be encoded into a single number $z = 2^x \\cdot 3^y$.  So if I want to say, "For every nonzero integers x, y, and z, it is not the case that $x^3 + y^3 = z^3$" I can actually just say, "There's no number $w$ such that there exist nonzero x, y, and z *less than w* with $w = 2^x \\cdot 3^y \\cdot 5^z$ and $x^3 + y^3 = z^3.$"  Thus, the three adjacent universal quantifiers over all x, y, and z can be combined.  However, if the sentence is "for all x there exists y", there's no way to translate that into a statement about a single number z, so only alike quantifiers can be collapsed in this way.\n\nWith these subtleties in hand, we can see, e.g., that Fermat's Last Theorem belongs in $\\Pi_1,$ since FLT says, "For *every* w greater than 2 and x, y, z greater than 0, it's not the case that $x^w + y^w = z^w.$  This implies that like any other $\\Pi_1$ statement, Fermat's Last Theorem should be falsifiable by brute force but not verifiable by brute force.  If a counterexample existed, we could eventually find it by brute force (even if it took longer than the age of the universe) and exhibit that example to decisively disprove FLT; but there's no amount of brute-force verification of particular examples that can prove the larger theorem.\n\n## How implications interact with falsifiability and verifiability\n\nIn general, if the implication $X \\rightarrow Y$ holds, then:\n\n- If $Y$ is falsifiable, $X$ is falsifiable.\n- If $X$ is verifiable, $Y$ is verifiable.\n\nThe converse implications do not hold.\n\nAs an example, consider the $\\Pi_2$ statement "For every prime $x$, there is a larger prime $y$".  Ignoring the existence of proofs, this statement is unfalsifiable by direct observation.  The falsifiable $\\Pi_1$ statement, "For every prime $x$, there is a larger prime $y = f(x) = 4x+1$ would if true imply the $\\Pi_2$ statement."  But this doesn't make the $\\Pi_2$ statement falsifiable.  Even if the $\\Pi_1$ assertion about the primeness of $4x+1$ in particular is false, the $\\Pi_2$ statement can still be true (as is indeed the case).  [comment:  Patrick, is there a particular reason we want this knowledge to be accessible to people who don't natively read logic?  I.e. were you making something else rely on it?]',
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